Math, asked by vinuthnals, 1 year ago

how much is 21a cube-17a square less than 89a cube-64a square+6a+16?

Answers

Answered by Anonymous
18
Heya ✋

Let see your answer !!!!!

21a^3 - 17a^2 - (89a^3 - 64a^2 + 6a + 16)

= 21a^3 - 17a^2 - 89a^3 + 64a^2 - 6a - 16

= 21a^3 - 89a^3 - 17a^2 + 64a^2 - 6a - 16

= - 68a^3 + 47a^2 - 6a - 16

Hence , 21a^3 - 17a^2 is - 68a^3 + 47a^2 - 6a - 16 less than 89a^3 - 64a^2 + 6a + 16.











Thanks :)))))
Answered by Deepsbhargav
15
☜☆☞hey friend ☜☆☞

here is your answer ☞
→_→→_→→_→→_→→_→

Required expression is

89a³ -64a²+6a+16-(21a² -17a²)

=89a³-64a²+6a+16 -21a³ + 17a²

On combining the like terms,

= 89a³-21a³– 64a²+17a² + 6a+16

= 68a³-47a² + 6a+16

So,

21a³ -17a². is. 68a³-47a² + 6a+16 less than 89a² -64a²+6a+16.

I think my answer is capable to clear your confusion

Devil_king▄︻̷̿┻̿═━一
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