Question

how much is 3p-4q+r less than 4p+3q-5r ​

Answer 1

✪ᴀɴsᴡᴇʀ✪

$(3p-4q+r)$ is $(p + 7q - 6r)$ less than $(4p+3q-5r)$.

★ᴇxᴘʟᴀɪɴᴀᴛɪᴏɴ★

Let $(3p-4q+r)$ is 'x' less than $(4p+3q-5r)$. Then

$\to 3p-4q+r = 4p+3q-5r - x$

$\to x= 4p+3q-5r - (3p-4q+r)$

$\to x= 4p+3q-5r - 3p + 4q - r$

$\to x= 4p- 3p +3q +4q - 5r - r$

$\to x= p + 7q - 6r$

Thus $(3p-4q+r)$ is $(p + 7q - 6r)$ less than $(4p+3q-5r)$.