how much is 4a²+5b-6 greater than 6a²-2b+10 ?
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Answer:
ii ) Horizontal method :
( 4a² + 5b² + 6ab ) + 3ab + ( 6a² - 2b² )
+ ( 4b² - 5ab )
= 4a² + 6a² + 5b² - 2b² + 4b² + 6ab + 3ab - 5ab
= ( 4 + 6 )a² + ( 5 - 2 + 4 )b² + ( 6 + 3 - 5 )ab
= 10a² + 7b² + 4ab ---( 2 )
( 1 ) = ( 2 )
From both methods ,
We get same answer.
I hope this helps you.
: )
Step-by-step explanation:
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