how much is 4x^2-3x+5 smaller than 7+5x^2-3x
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Answer\left[x _{1}\right] = \left[ \frac{1}{2} - \frac{3}{2}\,i \right][x1]=[21−23i]
much smaller . Algebra functional value
\left[x _{1}\right] = \left[ \frac{-3}{10}+\left( \frac{-1}{10}\,i \right) \,\sqrt{131}\right][x1]=[10−3+(10−1i)√131]
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