Question

how much is 4x²-9xy+3y²less than 2x²-y²+5xy​

Answer 1

Answer:

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Answer 2

Let's simplify step-by-step.

2x^2−y^2+5xy−(4x^2−9xy+3y^2)

Distribute the Negative Sign:

=2x^2−y^2+5xy+−1(4x^2−9xy+3y^2)

=2x^2+−y^2+5xy+−1(4x^2)+−1(−9xy)+−1(3y^2)

=2x^2+−y^2+5xy+−4x^2+9xy+−3y^2

Combine Like Terms:

=2x^2+−y^2+5xy+−4x^2+9xy+−3y^2

=(2x^2+−4x^2)+(5xy+9xy)+(−y^2+−3y^2)

=−2x^2+14xy+−4y^2

Answer:

=−2x^2+14xy−4y^2

Hope you find it helpful.