Question

How much is 6x^2 + 7y^2 +9 larger than -2x^2 +3y^2 + 11?

Answer 1

8 x^2 +4 y^2 -2............

Answer 2

Here is your answer

$(6x {}^{2} + 7y {}^{2} + 9) - ( - 2x {}^{2} + 3y {}^{2} + 11) \\ = 6x {}^{2} + 7y {}^{2} + 9 + 2x {}^{2} - 3y {}^{2} - 11 \\ = 8x {}^{2} + 4y {}^{2} - 3 \\ so \: 8x {}^{2} + 4y {}^{2} - 3 \: is \: larger$
Hope it helps you