Question

how much is a+ab–c greater than 2z+4b–5c?
This is Algebra :) pls solve ​

Answer 1

Step-by-step explanation:

Answer:a+ab-4b-2z+4cExplanation:Let A = a+ab-c,B = 2z+4b-5c,Difference of A and B = A-B= (a+ab-c) - (2z+4b-5c)= a+ab-c-2z-4b+5c= a+ab-4b-2z+(-c+5c)= ..a + ab - 4b-2z+2c

Answer 2

Answer:

Given:- If -1 is a zero of the polynomial p(x)= 2 -7x-8 , then the other zero is

Answer:- So, the other zero is 8.

Solution:- Let the zeroes be a and b Then, a=-1 , a + b= - (-7)/1 Hence, b = 7+1 = 8

Step-by-step explanation:

Hence, The answer will be 7x+5