Question

how much is a+ab–c greater than 2z+4b–5c? This is Algebra :) pls solve
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Answer 1

Answer:

a+ab-4b-2z+4c

Step-by-step explanation:

Let a = a+ab-c

b = 2z+4b-5c

Difference of A and B

=A - B

=(a+ab-c) - (2z+4b-5c)

=a+ab-c-2z-4b+5c

=a+ab-4b-2z+(-c+5c)

=a+ab-4b-2z+4c

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