Question

How much is a²-2ab+3b² less than 2a²-3b²+ab?

Answer 1

☆Hello friend☆
$\: \: \: \: 2 {a}^{2} - 3 {b}^{2} + ab \\ - ({a}^{2} - 2ab + 3 {b}^{2})$
2a^2-3b^2+ab
- a^2 -3b^2+2ab
= a^2-6b^2+3ab

Hope it helps

☺☺☺

Answer 2

We can simply subtract the smaller one from the bigger and we will get our answer that is :-
2a^2 - 3b^2  +ab - (a^2 -+ 3b^2 - 2ab)
2a^2 - 3b^2 +ab - a^2 - 3b^2 +2ab
2a^2 - a^2 -3b^2 -3b^2 +ab +2ab
a^2 - 6b^2 + 3ab
Hence a^2 - 2ab+3b^2 is less than 2a^2 - 3b^2 + ab by a^2 - 6b^2 + 3ab