Question

how much is consumed when j ampere of energy flow through the filament of the heater having resistnce of 100 ohms for two hours. express in joules(j).

Answer 1

Answer:

Hope this will help you

Answer 2

Answer:

Explanation:

Given:

Current (I) = 5 A

Resistance(R ) = 100 Ω

Time (t) = 2 h

Power( P) = I²R

P = (5)² × 100 watt

P = 25 × 100

P = 2500 watts

P =2.5 kW

[ 1 watt = 1/1000 kW]

Energy consumed (E) = P x t

[The electrical energy consumed by an electrical appliance is given by the product of its power rating and the time for which it is used]

E = 2.5 x 2

E = 5 kWh

•The commercial unit of electrical energy is kilowatt hour (kWh).

E = 5 × 3.6 × 10^6 J

[1kWh = 3.6 ×10^6 J]

E = 18.0×10^6 J