Math, asked by rajnandinithalkari25, 1 month ago

how much is minus 6 x square + 7 y cube is greater than than to x square minus y cube​

Answers

Answered by tryellmason30
0

Answer:

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Answered by harshitha202034
1

Answer :

 - 6 {x}^{2}  + 7 {y}^{3}  \\  \:  \:  \:  \:  \:  {x}^{2}  -  {y}^{3}  \\ ( - ) \: ( - ) \\  -  -  -  -  -  -  \\  - 7 {y}^{2}  + 8 {y}^{3}  \\  -  -  -  -  -  - \\ \\ - 6 {x}^{2}  + 7 {y}^{3}  \:  \: is \:  \: - 7 {y}^{2}  + 8 {y}^{3} \:  \: greater  \\ than  \:  \: to \:  \: {x}^{2}  -  {y}^{3}

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