How much is the angular distance between theTropic of cancer and Tropic of Capricorn? 40,50,47
Answers
Answered by
0
Answer:
47°
Explanation:
The angular distance between the Tropic of Cancer and the equator is 23°30'and that between the Tropic of Capricorn and the equator is 23°30'. So the angular distance between the Tropic of Cancer and the Tropic of Capricorn is 46°60', or approximately 47°
Similar questions
Math,
2 days ago
Computer Science,
2 days ago
English,
5 days ago
Math,
8 months ago
Art,
8 months ago