how much is x^2 + y^2 + 2xy + 9 greater than 3xy + 9x^2 + 9y^2 - 3
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Answered by
1
Answer: -8x^2 - 8y^2 - xy + 12
Step-by-step explanation: For doing these problems , take simple examples as - how much 5 is greater than 3 ? The answer is simply 5 - 3 = 2 . So for how much x^2 + y^2 + 2xy + 9 greater than 3xy + 9x^2 + 9y^2 - 3 , the answer is to just subtract them . So -
x^2 + y^2 + 2xy + 9 - 3xy - 9x^2 - 9y^2 + 3
⇒- 8x^2 - 8y^2 - xy + 12
Answered by
1
Answer:
-8x^2 -8y^2 -xy +12
Step-by-step explanation:
just by subtracting second from first
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