Question

how much is x^2 + y^2 + 2xy + 9 greater than 3xy + 9x^2 + 9y^2 - 3​

Answer 1

Answer: -8x^2 - 8y^2 - xy + 12

Step-by-step explanation: For doing these problems , take simple examples as - how much 5 is greater than 3 ? The answer is simply 5 - 3 = 2 . So for how much x^2 + y^2 + 2xy + 9 greater than 3xy + 9x^2 + 9y^2 - 3 , the answer is to just subtract them .  So -

x^2 + y^2 + 2xy + 9 - 3xy - 9x^2 - 9y^2 + 3

⇒- 8x^2 - 8y^2 - xy + 12

Answer 2

Answer:

-8x^2 -8y^2 -xy +12

Step-by-step explanation:

just by subtracting second from first