How much is x^3-2x^2+ x + 4 greater than 2x + 7x^2-5x + 6
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Answer: (x^3 - 2x^2 + x + 4) - (2x^3 + 7x^2 - 5x + 6)
= (1-2)x^3 + (-2-7)x^2 + (1-5)x + (4-6)
= -x^3 - 9x^2 - 5x - 2
= -(x^3 + 9x^2 + 5x + 2)
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