Question

how much is x² +2x+1 greater than x² -2x +1?...answer in detail ...and I will mark you as brainliest.....​

Answer 1

Answer:

4x

Step-by-step explanation:

Lets say

${x}^{2} + 2x + 1$

is equation 1.

and

${x}^{2} - 2x + 1$

is eqauation 2.

performing : equation 1- equation 2

this will give us

${x}^{2} + 2x + 1 - {x}^{2} + 2x - 1$

which is equals to 2x.

Mark it brainliest if it helped you.

Peace.

Answer 2

Answer:

hello mate..

Step-by-step explanation:

(1+x

2

)

2

(1+x)

n

=A

0

+A

1

x+A

2

x

2

−−−−−−−(1)

putx=0

then

(1)(1)=A

o

∴A

o

=1

Now,

differentiatingequ:(1)

2(1+x

2

)(2x)(1+x)

n

+n(1+n)

n−1

(1+x

2

)

2

=A

1

+2A

2

×x

Again,putx=0

n=A

1

orA

1

=n

Again,differentiatngw.r.t,

2.2x(2x)(1+x)

n

+4(1+x

2

)(1+x)

n

+2n(1+x

2

)(2x)(1+n)

n−1

+n(n−1)(1+x)

n−2

(1+x

2

)

2

+n2(1+x

n−1

)(1+x

2

)2x=2A

2

putx=0

⇒4+n(n−1)=2A

2

A

2

=

2

4+n

2

−n

A

0

,A

1

,A

2

,−−→A.P

Wecansay,

⇒1,n,

2

n

2

−n+4

⇒n−1=

2

n

2

−n+4

−n

⇒2n−1=

2

n

2

−n+4

⇒4n−2=n

2

−n+4

⇒n

2

−5n+6=0

⇒n

2

−3n−2n+6=0

⇒n(n−3)−2(n−3)=0

⇒(n−3)(n−2)

∴n=2,3

hope you get your answer