Math, asked by NOORANOORUDHEEN, 11 months ago

how much is x3-2x2+x+4 greater than 2x3+7x2-5x+6

Answers

Answered by hiranmoyeedas456
28

Answer:

-x^3-9x^2+6x-2

Step-by-step explanation:

(x^3-2x^2+x+4) - (2x^3-7x^2-5x+6)

=x^3-2x^2+x+4-2x^3-7x^2+5x-6

=x^3-2x^3-2x^2-7x^2+x+5x+4-6

=-x^3-9x^2+6x-2

hope this helps you..

Answered by neelamdhiwar
4

Answer:

-x3 - 9x2 + 6x - 2

Step-by-step explanation:

x3 - 2x2 + x +4 - ( 2x3 + 7x2 - 5x + 6 )

x3 - 2x2 + x +4 - 2x3 - 7x2 + 5x - 6

x3 -2x3 - 2x2 - 7x2 + x + 5x + 4 - 6

- x3 - 9x2 + 6x - 2

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