how much is x3-2x2+x+4 greater than 2x3+7x2-5x+6
Answers
Answered by
28
Answer:
-x^3-9x^2+6x-2
Step-by-step explanation:
(x^3-2x^2+x+4) - (2x^3-7x^2-5x+6)
=x^3-2x^2+x+4-2x^3-7x^2+5x-6
=x^3-2x^3-2x^2-7x^2+x+5x+4-6
=-x^3-9x^2+6x-2
hope this helps you..
Answered by
4
Answer:
-x3 - 9x2 + 6x - 2
Step-by-step explanation:
x3 - 2x2 + x +4 - ( 2x3 + 7x2 - 5x + 6 )
x3 - 2x2 + x +4 - 2x3 - 7x2 + 5x - 6
x3 -2x3 - 2x2 - 7x2 + x + 5x + 4 - 6
- x3 - 9x2 + 6x - 2
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