How much is x³-5x²-x+6 greater than 2x³-x²+4x+3?
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Answer :
x³ - 5x² - x + 6 - (2x³ - x² + 4x + 3)
= x³ - 5x² - x + 6 - 2x³ + x² - 4x - 3
= x³ - 2x³ - 5x² + x² - x - 4x + 6 - 3
= - x³ - 4² - 5x + 3
Hope this helps you
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