How much is y³-4y² + 6y –3 less than 2y³ + 7y + 8 ?
Answers
Answered by
7
Answer:
(y³- 4y²+ 6y-3)- ( 2y³+ 7y+8)
= y³-4y²+ 6y-3- 2y³- 7y- 8
= - y³- 4y²- y- 11
Hope it Helps
Answered by
1
Answer:
y^3+4y^2+y+11
Step-by-step explanation:
For Explanation, Refer to the Attachment.
I hope it helps.
Mark my answer as Brainliest.
Attachments:
Similar questions