Math, asked by akshitarajput14, 2 months ago

how much is y⁴-12y²+y+14 greater than 17y³+34y²-51y+68?

Answers

Answered by shreeyasahoo123

16

Answer:

y⁴-17y³-46y³+52y-54

Step-by-step explanation:

(y⁴-12y²+y+14)-(17y³+34y²-51y+68)

=y⁴-12y²+y+14-17y³-34y²+51y-68

=y⁴-17y³-12y²-34y²+51y+y+14-68

=y⁴-17y³-46y³+52y-54

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