Math, asked by mohdasif138, 1 year ago

how much large is
13x - 7y2

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Answers

Answered by sijasubbiah
2

Hey

Here is your answer,

To find the difference between the two numbers, we need to subtract it

= 13x^2 - 7y^2 - (6x^2 - 9y^2 )
= 13x^2 - 7y^2 - 6x^2 + 9y^2
= 7x^2 + 2y^2

Therefore, 13x^2 - 7y^2 is 7x^2 + 2y^2 larger than 6x^2 - 9y^2

Hope it helps you!


mohdasif138: OK
mohdasif138: thank you for help
Answered by Panzer786
1
Heya !!

Subtracting 6X² - 9Y² from 13X² - 7Y²

=> 13X² - 7Y² - (6X² - 9Y² )

=> 13X² - 7Y² - 6X² + 9Y²

=> 7Y² + 3Y²

Hence,

13X² - 7Y² is greater than 6X² -9Y² by 7X² + 2Y².
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