how much large is
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2
Hey
Here is your answer,
To find the difference between the two numbers, we need to subtract it
= 13x^2 - 7y^2 - (6x^2 - 9y^2 )
= 13x^2 - 7y^2 - 6x^2 + 9y^2
= 7x^2 + 2y^2
Therefore, 13x^2 - 7y^2 is 7x^2 + 2y^2 larger than 6x^2 - 9y^2
Hope it helps you!
mohdasif138:
OK
Answered by
1
Heya !!
Subtracting 6X² - 9Y² from 13X² - 7Y²
=> 13X² - 7Y² - (6X² - 9Y² )
=> 13X² - 7Y² - 6X² + 9Y²
=> 7Y² + 3Y²
Hence,
13X² - 7Y² is greater than 6X² -9Y² by 7X² + 2Y².
Subtracting 6X² - 9Y² from 13X² - 7Y²
=> 13X² - 7Y² - (6X² - 9Y² )
=> 13X² - 7Y² - 6X² + 9Y²
=> 7Y² + 3Y²
Hence,
13X² - 7Y² is greater than 6X² -9Y² by 7X² + 2Y².
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