Question

How much leads of specific gravity 11 must be added to a piece of cork of specific
gravity 0.2 weighing 10 g so that it just floats on water?
a) 2.2 g b) 4.4 g c) 44 g d) 440g

Answer 1

Hi!!!

Answer:Your answer will be ;- 44 gms

Explanation:We want the specific gravity to end up being one, exactly that of waters.

Cork specific gravity = 0.2

Specific gravity = density of object ÷ density of water.(Density of water = 1 )

So,

density of Cork will be = 0.2 × 1 = 0.2

And density of lead will be = 11 × 1 = 11

Density = mass ÷ volume.

So, volume of Cork = 10g ÷ 0.2 = 50

"we need to get the mass/volume ratio equal to waters. "

Mass of lead will be = 11 × v

( v = volume of lead, assumed)

So,

the total mass we will have is = (10 + 11v) gm

And total vol. will be = (50 + v)L

---->(10 + 11v) / (50+v) = 1

---->10 + 11v = 50 + v

---->10v = 40

---->v =4 L

So,

we need 4 extra water volumes of lead which is equal to 44gm extra masses.

Mass of lead = 11 × 4 = 44gm.

Hope you get the answer.

Pleased to help you.

Answer 2

Answer:

(a) 2.2

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