Math, asked by paramitaghosh27, 9 months ago

How much less is x^2-2xy+3y^2 than 2x^2-3y^(2 )+xy ? Plz answer fast

Answers

Answered by EuphoricEpitome
5

Question :

How much less is x²-2xy+3y² than 2x²-3y²+xy?

Answer :

(2x²-3y²+xy)-(x²-2xy+3y²)

= 2x²-3y²+xy-x²+2xy -3y²

= (2x²-x²)+(xy+2xy)+(-3y²-3y²)

= x²+3xy-6y²

{\pink{\boxed{ Answer = x^2+3xy-6y^2 }}}

Additional Information -

Types of Algebraic expressions -

On the basis of degree

→Linear

→Quadratic

→Cubic

→Biquadratic

On the basis of variables

→ One variable

→Two variables

Answered by bhuvanatheertha
0

Answer:

x square +3 x y - 6 y square

Step-by-step explanation:

(2x square -3 y square+ x y ) - (x square- 2x y+ 3 y square)

=2x square-3 y square- x square+2 x y- 3 y square

=(2 x square- x square)+(x y+ 2 x y ) + (-3y square-3y square)

=x square+ 3 x y- 6 y square

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