How much less is x^2-2xy+3y^2 than 2x^2-3y^(2 )+xy ? Plz answer fast
Answers
Answered by
5
★Question :
How much less is x²-2xy+3y² than 2x²-3y²+xy?
★Answer :
(2x²-3y²+xy)-(x²-2xy+3y²)
= 2x²-3y²+xy-x²+2xy -3y²
= (2x²-x²)+(xy+2xy)+(-3y²-3y²)
= x²+3xy-6y²
★Additional Information -
Types of Algebraic expressions -
On the basis of degree
→Linear
→Quadratic
→Cubic
→Biquadratic
On the basis of variables
→ One variable
→Two variables
Answered by
0
Answer:
x square +3 x y - 6 y square
Step-by-step explanation:
(2x square -3 y square+ x y ) - (x square- 2x y+ 3 y square)
=2x square-3 y square- x square+2 x y- 3 y square
=(2 x square- x square)+(x y+ 2 x y ) + (-3y square-3y square)
=x square+ 3 x y- 6 y square
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