Question

How much lime can be obtained by heating 200kg limestone which is 95% pure?

Answer 1

95% of 200 kg = 190 kg.

The molar mass of CaCO₃ is 100 g/mol, so 190 kg = (190,000 g)/(100 g/mol)

= 1900 mol.

CaCO₃ → CaO + CO₂, so 1900 mol of CO₂ are removed by heating. The molar mass of CO₂ is 44 g/mol, so 1900 mol = (1900 mol)(44 g/mol) = 83 600 g = 83.6 kg.

190 kg - 83.6 kg = 106.4 kg CaO.