How much limestone is needed to obtain 56 g of quicklime ? Atomic masses are :
Ca = 40 u, C = 12 u and 0 = 16 u.
Please tell as fast as possible.
Correct answer only please.
Answers
Answered by
0
Answer:
CaCO
3
Δ
CaO+CO
2
↑
Molar masses of CaO and CaCO
3
are 56 g/mol and 100 g/mol respectively.
Mass of CaO=56 kg=56000 g
(∵1 kg=1000 g)
Number of moles of CaO=
56 g/mol
56000 g
=1000 mol
As per balanced chemical equation, 1 mole of CaO is obtained by heating 1 mole of CaCO
3
.
Hence, 1000 moles of CaO will be obtained by heating 1000 moles of CaCO
3
.
Mass of CaCO
3
=1000 mol×100 g/mol=10
5
g
Convert unit from g to kg.
Mass of CaCO
3
=10
5
g×
1000 g
1 kg
=100 kg
Explanation:
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Answered by
1
Answer:
1 mole CaCO3
Explanation:
- CaCO3 gives CaO+CO2
- 1 mole of limestone gives 1 mole of quicklime
- hence 1 mole CaCO3 will be required which is equal to 100gms
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