How much marble of 96.5% purity would be required to prepare 100 litres of carbon dioxide at STP when marble is acted upon by dil HCL?
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Explanation:
22.4 L of C02 at N.T.P. is obtained from CaC03 = 100g 100 L of C02 at N.T.P. will be obtained from CaC03 100 = —x 100 = 446.4 g 22.4 446.4 x 100 mpure marble required = 462.6 g• 96.5 0 63.Jul 4, 2019
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