how much mass of 40% NaOH is required to react with 500 ml, 0.3 M H3PO4 solution?
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Answer:
The Answer is 8 grams of NaOH.
Some pre-requisite knowledge to solve the question are:
Molar mass of NaOH = 40u
Molarity = Mass of solute × 1000/(Molar mass of solute × Volume of solution in mL).
It is given that M=0.4 and V= 500mL.
By putting the values in formula we get:
0.4=Mass of NaOH ×1000/(40×500).
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