Question

. How much mass of silver nitrate will react with 5.85 g of sodium chloride to produce 14.35 g of silver chloride and 8.5 g of sodium nitrate if law of conservation of mass is followed? *​

Answer 1

Given - Mass of sodium chloride - 5.85 g

Mass of silver chloride - 14.35 g

Mass of sodium nitrate - 8.5 g

Find - Mass of silver nitrate formed.

Solution - Law of conservation of mass states that mass can neither be converted nor destroyed, it can only be transferred from one form to another. Thus, mass of reactants will be equal to mass of products.

The chemical reaction involving compounds in question is -

NaCl + AgNO3 --> AgCl + NaNO3,

where, NaCl is sodium chloride, AgNO3 is silver nitrate, AgCl is silver chloride and NaNO3 is sodium nitrate.

Let mass of silver nitrate be X. Hence, according to law of conservation of mass -

5.85 + X = 14.35 + 8.5

X = 20.2 - 5.85

X = 11.7 gram

Hence, 11.7 gram of silver nitrate in above reaction.