Question

how much mass of silver nitrate will react with 5.85g of sodium chloride to produce 14.35g of silver chloride and 8.5 g of sodium nitrate if law of conservation of mass is followed?​

Answer 1

Answer:

you can take the mass of silver nitrate as x

then the equation will be

AgNo3 + NaCl -- AgCl + NaNo3

i.e., x+ 5.85 -- 14.35+ 8.5

x= 14.35+8.5-5.85= 17 g

Explanation:

You can just add the masses of reactants and subtract the mass of sodium chloride from the sum you obtained

Answer 2

Answer:

17.00g

Explanation:

According to law of conservation of mass -

total mass of reactants side = total mass of products side

let mass of silver be x

x+5.85=14.35+8.5

x+5.85=22.85

x=22.85-5.85

x=17.00

hence, mass of silver nitrate =17.00g