Question

How much mechanical work is done in raising a 20.7 kg mass a distance of 2.69 metres? Note 1: This question is not direction specific. Therefore, if using acceleration due to gravity, please use positive 9.81 m/s/s.

Answer 1

Answer:

546.25 J

Explanation:

Given: Mass(m) = 20.7 kg

distance(s) = 2.69 m

acceleration due to gravity (g) = 9.81m/s²

To find: Work done = ?

formula:

$work \: = force \times displacement \:$

therefore,

work = mg × s

Substituting the values,

work = 20.7(9.81) × 2.69

= 203.067 × 2.69

work = 546.25 N-m

work = 546.25 Joules

Answer 2

Answer:

The work done is $546.25 J$.

Explanation:

Given that the mass(m) $= 20.7 kg$

Distance(s) $= 2.69 m$

Acceleration due to gravity (g) $= 9.81m/s^2$

We have to find the work done.

We know that work done is the product of magnitude of displacement $s$ and the component of force which is in the direction of displacement.

Here, it is given that direction is not to be considered.

We know that the formula for work done is force × displacement

i.e. work $=$ mg × s

Substituting the above given values,

work $= 20.7*9.81 * 2.69$

$= 203.067 * 2.69$

$=546.25Nm$

$=546.25J$

Hence the work done is $546.25$ joules.