Question

How much mechanical work must be done to completely melt 1 gram of ice at 0c?

Answer 1

Heat required is given by

Q=M×S1(T2-T1)+M×L1+M×S2×(T3-T2)+M×L2 ,Where

L1=latent heat of fusion of water 334 jule/gr.

L2=latent heat of vaporisation of water 2258 j/g

S1=specific heat of ice 0.50 cal/g=2.093 j/g

S2=specific heat of water 4.186 j/g

Q=1×2.093×(0+10)+1×334+1×4.186×(100-0)+1×2258

Q=3031.53 jule

Or

Q=724.20 calorie