Math, asked by ramya320858, 10 months ago

How much metal is required to make a 20 metre long pipe, if its inner and outer diameter are 6 metre and 8 metre respectively.

Answers

Answered by mysticd
1

 \underline {\pink{ Dimensions \: of \: a \: metal \:pipe : }}

 Length \:of \:the \: pipe (h) = 20 \:m

 Inner \: Diameter (d) = 6 \:m

 Inner \: radius (r) = \frac{d}{2}

 = \frac{6}{2}

 = 3 \: m

 Outer \: Diameter (D) = 8\:m

 Outer \: radius (R) = \frac{D}{2}

 = \frac{8}{2}

 = 4 \: m

 \red{ Metal \: required \: to \: make \:the \:pipe }

 = \pi h ( R^{2} - r^{2} )

 = \pi h ( R + r )( R - r )

 = \frac{22}{7} \times 20 \times ( 4 + 3 )( 4 - 3 )

 = \frac{22}{7} \times 20 \times 7 \times  1

= 22\times 20

= 440 \: m^{3}

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