How much metal sheet is required to make a closed cylindrical tank of height 50 cm and diameter
of base 112 cm? Find the area of the metal sheet in sq. m.
Answers
Step-by-step explanation:
Given:-
a closed cylindrical tank of height 50 cm and diameter of base 112 cm
To find:-
How much metal sheet is required to make a closed cylindrical tank of height 50 cm and diameter of base 112 cm? Find the area of the metal sheet in sq. m.?
Solution:-
Diameter of the closed cylindrical tank (d)=112 cm
Radius (r)=Diameter/2
=>r=112/2
=>r=56 cm
Radius of the cylindrical tank= 56 cm
Height of the cylindrical tank (h)=50 cm
The required metal sheet to make a closed cylindrical tank is its total surface area.
=>Total surface area of the cylinder
=>2πr(r+h) sq.units
=>2(22/7)×56(56+50) sq.cm
=>(2×22×56×106)/7 sq.cm
=>2×22×8×106 sq.cm
=>37312 sq.cm
Total surface area of the cylindrical tank =
37312 sq.cm
We know that 1 sq.m = 10000 sq.cm
1 sq.cm = 1/10000 sq.m
=>37312 sq.cm = 37312/10000 sq.m
=>37312 sq.cm = 3.7312 sq.m
Answer:-
Required area of the metal sheet to make a closed cylindrical tank = 37312 sq.cm
Area of the metal sheet in sq.meters = 3.7312 sq.m
Used formula:-
Total surface area of a cylinder whose radius is "r" units and height is "h" units = 2πr(r+h) sq.units
Where, π=22/7