how much metal sheet is required to make an open cylindrical tank of radius 4.2 M and height 1
5 m
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Answered by
3
radius is 4.2 meter
here
circumference = length of the metal sheet
height = breadth of the metal sheet
circumference =2*22/7*4.2(4.2 is radius)
length =26.4m
breadth = 15 m
hence we need a metal sheet of dimensions 12.4m in length and 15 m in breadth
neha5770:
full answer give
Answered by
5
curved surface of a cylinder = 2πrh = 2×(22/7)×4.2×15 = 395.84 cm^2
area of the bottom of tank = πr^2 = (22/7)×(4.2)^2 = 55.4 cm^2
Total metal sheet required to make the tank = 395.84 + 55.4 = 451.25 cm^2
area of the bottom of tank = πr^2 = (22/7)×(4.2)^2 = 55.4 cm^2
Total metal sheet required to make the tank = 395.84 + 55.4 = 451.25 cm^2
is it correct
yes, 100% correct
really
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