how much metal sheet is required to make an open cylindrical tank of radius 4.2 M and height 15 m
Answers
Answered by
7
Answer:
451.44 m^2
Step-by-step explanation: (¤)=pi
Metal sheet required= csa of cylinder + base area
= 2¤rh + ¤r^2
= 2 × 22/7 × 4.2 × 15 + 22/7 × 4.2 × 4.2
= 396 + 55.44
= 451.44 m^2
#MarkAsBrainliest
abhishekgupta2594:
t y
Answered by
1
Here is your answer in attachment
hope it help you
hope it help you
Attachments:
Similar questions
English,
7 months ago
Math,
7 months ago
Economy,
7 months ago
Computer Science,
1 year ago
English,
1 year ago