how much metal sheet is required to make an open cylindrical tank of radius 4.2 M and height 15 m
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Answer:
451.44 m^2
Step-by-step explanation: (¤)=pi
Metal sheet required= csa of cylinder + base area
= 2¤rh + ¤r^2
= 2 × 22/7 × 4.2 × 15 + 22/7 × 4.2 × 4.2
= 396 + 55.44
= 451.44 m^2
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