How much minimum volume of CO at STP is needed to react completely with 0.112L of O2, to produce CO2 ?
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Answer:
CaCO
3
+2HCl⟶CaCl
2
+H
2
CO
3
HCl is limiting reagent so the moles of H
2
CO
3
=10
−1
mol
Now-
H
2
CO
3
⟶H
2
O+CO
2
n mole of H
2
CO
3
will give same amount of mole for CO
2
The no. of mole of CO
2
=10
−1
mole
The volume of CO
2
-
mole=
22.4
Volume
10
−1
=
22.4
volume
Volume=2.24L
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