How much momentum will a dub bell of mass 10kg transfer to the floor if it falls from a height of 80m take its downward acceleration to be 10 metre per second square.
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Mass of bell is 10kg
height, s=80/100 m = 0.8 m
a = 10m/s
u = 0
Using : v^2 = u^2 + 2as
= 4m/s
Momentum = MV
10kg × 4m/s
= 40kgm/s
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Answered by
4
Answer:
Mass of bell is 10kg
height, s=80/100 m = 0.8 m
a = 10m/s
u = 0
Using : v^2 = u^2 + 2as
4m/s
Momentum = MV
10kg × 4m/s
40kg m/s
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