Question

how much momentum will a dubbell of mass 10kg transfer to the floor if it falls from a height of 80m take its downward acceleration to be 10 metre per second.​

Answer 1

Explanation:

$\huge\mathfrak\red{ANSWER}$

mass of bell is 10kg

height, s=80/100 m = 0.8 m

a = 10m/s

u = 0

Using : v^2 = u^2 + 2as

= 4m/s

Momentum= 10kg × 4m/s = 40kgm/s.

Answer 2

Answer:

Heya!

Explanation:

mass of bell is 10kg

height, s=80/100 m = 0.8 m

a = 10m/s

u = 0

Using : v^2 = u^2 + 2as

= 4m/s

Momentum = 10×4 = 40kgm/s