Question

how much momentum will a dubbell of mass 10kg transfer to the floor if it falls from a height of 80m take its downward acceleration to be 10 metre per second.​

Answer 1

Explanation:

$\huge\mathfrak\red{ANSWER}$

mass of bell is 10kg

height, s=80/100 m = 0.8 m

a = 10m/s

u = 0

Using : v^2 = u^2 + 2as

= 4m/s

Momentum = 10×4 = 40kgm/s

Answer 2

Answer:

m=10kg

h=80m

g=10ms^-2

p=?

u=ms^-1

v^2-u^2=2gh

v^2-0^2=2×10×80

v^2=1600

v=40

p=m×v

p=10×40

p=400 kgms^-1

Explanation:

use newton's 3rd eqn of motion to find v..take u=0 as it is a case of freelfall...now find p by multiplying mass and velocity