how much momentum will a dum-bell of mass 25 kg transfer to the floor if it falls from a height of 50 cm ? take its down ward acceleration 10 m/s^2
Answers
Answered by
4
since P=MV
take 3rd equation of motion v^2 = u^2+ 2gh
from this we got v=√10m/s
therefore, from p=mv
p=(25×√10)kg-m/s
take 3rd equation of motion v^2 = u^2+ 2gh
from this we got v=√10m/s
therefore, from p=mv
p=(25×√10)kg-m/s
Similar questions