Question

How much momentum will a dummb bell of mass 10 kg transfer to the floor if it falls from a height of 80cm ? take its downward acceleration to be 10 ms^ -2.​

Answer 1

Hii Doraemon!

Your answer is as follows..

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We have,

• Mass of bell = 10 kg
• Height from which it is dropped = 80 cm = 0.8 m
• Downward acceleration = 10 m/s²

And also,

• Momentum = Mass × velocity

Let us find the velocity of the bell,

• 2as = v² - u²

u = 0 because it will be released from rest state.

• 2(10)(0.8) = v² - 0²
• 16 = v²
• √16 = v
• 4 = v

Therefore, the velocity of the bell is 4 m/s

Put the values of mass and velocity in the formula of momentum;

• Momentum = Mass × velocity
• p = 10 × 4
• p = 40 kg m/s

Therefore, momentum of the bell on hitting the ground will be 40 kg m/s.

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Thank youu!! :))

Answer 2

Hi Doraemon,

____________________________________

We have,

We have,○Mass of bell = 10 kg

We have,○Mass of bell = 10 kg○Height from which it is dropped = 80 cm = 0.8 m

We have,○Mass of bell = 10 kg○Height from which it is dropped = 80 cm = 0.8 m○Downward acceleration = 10 m/s²

We have,○Mass of bell = 10 kg○Height from which it is dropped = 80 cm = 0.8 m○Downward acceleration = 10 m/s² ○Momentum = Mass × velocity

We have,○Mass of bell = 10 kg○Height from which it is dropped = 80 cm = 0.8 m○Downward acceleration = 10 m/s² ○Momentum = Mass × velocityLet us find the velocity of the bell,

We have,○Mass of bell = 10 kg○Height from which it is dropped = 80 cm = 0.8 m○Downward acceleration = 10 m/s² ○Momentum = Mass × velocityLet us find the velocity of the bell,•2as = v² - u²

We have,○Mass of bell = 10 kg○Height from which it is dropped = 80 cm = 0.8 m○Downward acceleration = 10 m/s² ○Momentum = Mass × velocityLet us find the velocity of the bell,•2as = v² - u²u = 0 because it will be released from rest state.

We have,○Mass of bell = 10 kg○Height from which it is dropped = 80 cm = 0.8 m○Downward acceleration = 10 m/s² ○Momentum = Mass × velocityLet us find the velocity of the bell,•2as = v² - u²u = 0 because it will be released from rest state.•2(10)(0.8) = v² - 0²16 = v²√16 = v4 = v

We have,○Mass of bell = 10 kg○Height from which it is dropped = 80 cm = 0.8 m○Downward acceleration = 10 m/s² ○Momentum = Mass × velocityLet us find the velocity of the bell,•2as = v² - u²u = 0 because it will be released from rest state.•2(10)(0.8) = v² - 0²16 = v²√16 = v4 = vTherefore, the velocity of the bell is 4 m/s

We have,○Mass of bell = 10 kg○Height from which it is dropped = 80 cm = 0.8 m○Downward acceleration = 10 m/s² ○Momentum = Mass × velocityLet us find the velocity of the bell,•2as = v² - u²u = 0 because it will be released from rest state.•2(10)(0.8) = v² - 0²16 = v²√16 = v4 = vTherefore, the velocity of the bell is 4 m/sPut the values of mass and velocity in the formula of momentum;

We have,○Mass of bell = 10 kg○Height from which it is dropped = 80 cm = 0.8 m○Downward acceleration = 10 m/s² ○Momentum = Mass × velocityLet us find the velocity of the bell,•2as = v² - u²u = 0 because it will be released from rest state.•2(10)(0.8) = v² - 0²16 = v²√16 = v4 = vTherefore, the velocity of the bell is 4 m/sPut the values of mass and velocity in the formula of momentum;•Momentum = Mass × velocity

We have,○Mass of bell = 10 kg○Height from which it is dropped = 80 cm = 0.8 m○Downward acceleration = 10 m/s² ○Momentum = Mass × velocityLet us find the velocity of the bell,•2as = v² - u²u = 0 because it will be released from rest state.•2(10)(0.8) = v² - 0²16 = v²√16 = v4 = vTherefore, the velocity of the bell is 4 m/sPut the values of mass and velocity in the formula of momentum;•Momentum = Mass × velocity•p = 10 × 4

We have,○Mass of bell = 10 kg○Height from which it is dropped = 80 cm = 0.8 m○Downward acceleration = 10 m/s² ○Momentum = Mass × velocityLet us find the velocity of the bell,•2as = v² - u²u = 0 because it will be released from rest state.•2(10)(0.8) = v² - 0²16 = v²√16 = v4 = vTherefore, the velocity of the bell is 4 m/sPut the values of mass and velocity in the formula of momentum;•Momentum = Mass × velocity•p = 10 × 4•p = 40 kg m/s

We have,○Mass of bell = 10 kg○Height from which it is dropped = 80 cm = 0.8 m○Downward acceleration = 10 m/s² ○Momentum = Mass × velocityLet us find the velocity of the bell,•2as = v² - u²u = 0 because it will be released from rest state.•2(10)(0.8) = v² - 0²16 = v²√16 = v4 = vTherefore, the velocity of the bell is 4 m/sPut the values of mass and velocity in the formula of momentum;•Momentum = Mass × velocity•p = 10 × 4•p = 40 kg m/sTherefore, momentum of the bell on hitting the ground will be 40 kg m/s.(Ans)

Hope it helps you:) <3

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