Physics, asked by ashiquearya, 1 year ago

How much momentum will an object of mass 10 kg is transfer to the floor if it fall from a height of 5m (g=10m s-2)


natsu1044q: 25

Answers

Answered by BlankNGNL
1
Assuming It is an Inelastic collision.
Momentum = mv -0= 10*(2*10*5)^1/2= 100 kg-m/s
Answered by saka82411
1
Hi friend,

We know that ,

S=1/2 at²

t²= 2S/a

t²= 1

t= 1 sec.

:- v= 10m/s

Momentum (p)= MV

P= 10×10

P=100 Kg m/s.

Hope this helped you a little!!!

saka82411: That is the formula
BlankNGNL: No I mean Like the text in the answers.
saka82411: This is also a form of solution to this answer
BlankNGNL: No how do you write it. How did you write the t^2.
saka82411: S=ut+1/2 at²
saka82411: By bring all the others to left side t² will be get
natsu1044q: s-ut-1/2=t^2
natsu1044q: sorry
saka82411: No probs.
BlankNGNL: Uh.. Thanks But I am not asking about a theory related doubt. It was a technical. Never Mind.
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