How much momentum will an object of mass 10 kg is transfer to the floor if it fall from a height of 5m (g=10m s-2)
natsu1044q:
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Answers
Answered by
1
Assuming It is an Inelastic collision.
Momentum = mv -0= 10*(2*10*5)^1/2= 100 kg-m/s
Momentum = mv -0= 10*(2*10*5)^1/2= 100 kg-m/s
Answered by
1
Hi friend,
We know that ,
S=1/2 at²
t²= 2S/a
t²= 1
t= 1 sec.
:- v= 10m/s
Momentum (p)= MV
P= 10×10
P=100 Kg m/s.
Hope this helped you a little!!!
We know that ,
S=1/2 at²
t²= 2S/a
t²= 1
t= 1 sec.
:- v= 10m/s
Momentum (p)= MV
P= 10×10
P=100 Kg m/s.
Hope this helped you a little!!!
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