Question

How much momentum will an object of mass 10 kg transfer to the floor if it falls from a height of 5m?

Answer 1

Step-by-step explanation:

assuming g = 10 m/s^2

s = ut+ 0.5*g*t^2

5 = 0 + 0.5*10*t^2

t^2 = 10/10 = 1

t = 1 sec

v= u+g*t

v= 0 + 10*1 = 10 m/s

momentum = 10 *10 = 100 kg*m/sec