Question

How much momentum will an object of mass 10 kg transfer to the floor if it falls from a height of <br />5 m? (g=10m/s)​

Answer 1

Answer:

Given:

Mass = 10 kg

Height = 5 metres

To find:

Momentum transferred to the ground.

Concept:

The final momentum of the object (just before hitting the ground) will be transferred to the ground, if the collision is considered elastic.

Calculation:

Since the object is dropped, initial velocity of object is zero.

${v}^{2} = {u}^{2} + 2gh \\ = > {v}^{2} = {0}^{2} + (2 \times 10 \times 5) \\ = > {v}^{2} = 100 \\ = > v = \sqrt{100 } \\ = > v = 10 \: m {s}^{ - 1}$

So, final momentum of object just before hitting the ground .

$\therefore \: p1 = m \times v \\ = > p1 = 10 \times 10 \\ = > p1 = 100 \: kg \: m {s}^{ - 1}$

Momentum after hitting the ground :

$p2 = 0 \: kg \: m {s}^{ - 1}$

Hence, momentum change of the object is correspondingly transferred to the ground.

So , momentum sent to ground

$\therefore \: p2 - p1 \\ = 0 - 100 \\ = - 100 \: kg \: m {s}^{ - 1}$

So final answer :

$\boxed{ \huge{ \red{ - 100 \: kg \: m {s}^{ - 1}}}}$

Answer 2

Heya

☆Refer to the given attachment please