Question

How much momentum will an object of mass 10 kg transfer to floor if it falls from a height of 5m (g =10m/s)

Answer 1

HEY!!

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▶m = 10kg h = 5m g = 10 m/s u= 0 m/s

▶v^2 - u2 = 2gh

▶v^2 = 2 * 10 * 5

▶v^2 = 100

▶v = 10

▶▶p = mv = 10 * 10 = 100 kg m/s

Answer 2

Firstly the velocity will be calculated using third equation of motion.
Initial velocity, u =0 because it is free fall condition
V= to be calculated 
Height h = 5m
According third equation of motion
v2−u2=2as
v2−0= 2x10x5
v2=100m/s
v= 10m/s
Now, momentum p= m v
p=10x 10
p=100Kgm /s