Question

how much Momentum will an object of mass 10kg transfer to the floor if it falls at a height of 5m

Answer 1

here, mgh = 1/2 mv²

10×5 = 1/2 v²

v = √100 = 10m/s

p = MV

= 10 × 10

= 100 kg m/s



thus momentum = 100 Kg m /s

Answer 2

Here is your answer-

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Have to use work energy theoram-

Assuming ball will stop after collision.

$mgh = \frac{1}{2} m {v}^{2} \\ \\ gh = \frac{1}{2} {v}^{2} \\ v = \sqrt{10 \times 5 \times 2} \\ v = 10$
☆velocity of body is 10m/s

so momentum will be $\red{MV}$

➡️10×10

➡️100kg m/s