how much momentum will an object of mass 12kg transfer to the floor if it falls from a height of 0.8m(a=10m/s2)
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Answer:
48 kgm/s
Explanation:
u = 0
v = ?
s = 0.8m
a = 10m/s²
v² - u² = 2as
v² - 0 = 2×10×0.8 = 16
v = √16 = 4m/s
Momentum = mv = 12×4 = 48kgm/s
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