Question

How much momentum will an object of mass 20 kg transfer to the floor if it falls from a height of 200 m? (g = 10 m/s2)

Answer 1

Answer:

Applying work energy theorem

Kinetic energy = potential energy

$\frac{1}{2} mv {}^{2} = mgh \\ \\ v = \sqrt{2gh} \\ \\ mv \: = m \sqrt{2gh} \\ \\ p = m \sqrt{2gh} \\ \\ p = 20 \sqrt{2 \times 10 \times 200} \\ \\ p = 400 \sqrt{10} \: ms {}^{ - 1}$