Question

how much money did Priya invest in a company to get back 196830 in 3 years if the rate of interest is 8% per annum

Answer 1

Answer

AnswerMr. Sayyad:-

AnswerMr. Sayyad:-A=P(1+r)t

AnswerMr. Sayyad:-A=P(1+r)tA=40,000(1+0.08)2

AnswerMr. Sayyad:-A=P(1+r)tA=40,000(1+0.08)2A=40000(1.08)2

AnswerMr. Sayyad:-A=P(1+r)tA=40,000(1+0.08)2A=40000(1.08)2A=46656

AnswerMr. Sayyad:-A=P(1+r)tA=40,000(1+0.08)2A=40000(1.08)2A=46656CI=A−P=46656−40000

AnswerMr. Sayyad:-A=P(1+r)tA=40,000(1+0.08)2A=40000(1.08)2A=46656CI=A−P=46656−40000=6656Rs.

AnswerMr. Sayyad:-A=P(1+r)tA=40,000(1+0.08)2A=40000(1.08)2A=46656CI=A−P=46656−40000=6656Rs.Profit%=400006656×100=16.64%

AnswerMr. Sayyad:-A=P(1+r)tA=40,000(1+0.08)2A=40000(1.08)2A=46656CI=A−P=46656−40000=6656Rs.Profit%=400006656×100=16.64%Mr. Fernandes:-

AnswerMr. Sayyad:-A=P(1+r)tA=40,000(1+0.08)2A=40000(1.08)2A=46656CI=A−P=46656−40000=6656Rs.Profit%=400006656×100=16.64%Mr. Fernandes:-Profit =192000−120000

AnswerMr. Sayyad:-A=P(1+r)tA=40,000(1+0.08)2A=40000(1.08)2A=46656CI=A−P=46656−40000=6656Rs.Profit%=400006656×100=16.64%Mr. Fernandes:-Profit =192000−120000=72000

AnswerMr. Sayyad:-A=P(1+r)tA=40,000(1+0.08)2A=40000(1.08)2A=46656CI=A−P=46656−40000=6656Rs.Profit%=400006656×100=16.64%Mr. Fernandes:-Profit =192000−120000=72000Profit%=12000072000×100

AnswerMr. Sayyad:-A=P(1+r)tA=40,000(1+0.08)2A=40000(1.08)2A=46656CI=A−P=46656−40000=6656Rs.Profit%=400006656×100=16.64%Mr. Fernandes:-Profit =192000−120000=72000Profit%=12000072000×100=60%.

AnswerMr. Sayyad:-A=P(1+r)tA=40,000(1+0.08)2A=40000(1.08)2A=46656CI=A−P=46656−40000=6656Rs.Profit%=400006656×100=16.64%Mr. Fernandes:-Profit =192000−120000=72000Profit%=12000072000×100=60%.Clearly, Mr. Fernandes's investment was more profitable.

Answer 2

Answer:

158733.87 rs

Step-by-step explanation:

amount=186830

principle=x

time=3years

rate=8%

interest=x*3*8÷100

=12x/50

196830=x+12x/50

196830=62x/50

(solving)

x=158733.87