How much money must set aside each year so as to replace a machine that will cost rs. 15000 after 8 years? The rate of interest being 12% per year Compounded.
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Answer:
1017(approximately)
Step-by-step explanation:
If we insure a Principal amount of P at a compound interest at rate 'r' for a period of 'n' years, then principal along with interest would be equal to
=P(1+r)^n
But here , principal amount is insured every year for 8 years
Now, given r = 12%
For initial amt insured , P(1+r)^8
For amt insured after 1yr, P(1+r)^7
For amt insured after 2yr, P(1+r)^6
......so on till 8 yrs
So, total returns = P[(1+r)^8 + (1+r)^7 +.....+1 ] = 15000(given)
=>P[(1+r)^9-1]/r=15000 ( Sum to 9 terms of a G.P)
On simplification we get , P = 1017 rs(approximately.)
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