Math, asked by ik971328, 1 year ago

How much money must set aside each year so as to replace a machine that will cost rs. 15000 after 8 years? The rate of interest being 12% per year Compounded.

Answers

Answered by VEDULAKRISHNACHAITAN
10

Answer:

1017(approximately)

Step-by-step explanation:

If we insure a Principal amount of P at a compound interest at rate 'r' for a period of 'n' years, then principal along with interest would be equal to

=P(1+r)^n

But here , principal amount is insured every year for 8 years

Now, given r = 12%

For initial amt insured ,  P(1+r)^8

For amt insured after 1yr, P(1+r)^7

For amt insured after 2yr, P(1+r)^6

......so on till 8 yrs

So, total returns = P[(1+r)^8 + (1+r)^7 +.....+1 ] = 15000(given)

=>P[(1+r)^9-1]/r=15000    ( Sum to 9 terms of a G.P)

On simplification we get , P = 1017 rs(approximately.)


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