how much more than 2x²+4xy+2y² is 5x²+10xy-y²
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2x^2+4xy+2y^2 > 5x^2+10xy-y^2
(2x^2+4xy+2y^2)-(5x^2+10xy-y^2)
=2x^2+4xy+2y^2-5x^2-10xy+y^2
=- 3x^2-6xy+3y^2
(-3x^2-6xy+3y^2) is the answer
rankawatSamridhi1:
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Answer:
-3x^2 - 6xy + 3y^2
Is the answer
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